Chapter 9: Reaction Mechanisms, Pathways, Bioreactions and Bioreactors


Topics

  1. Active Intermediates/Free Radicals
  2. Enzymes
  3. Bioreactors
  4. Pharmacokinetics
  5. Polymerization


Active Intermediates / Free Radicals (PSSH)

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An active intermediate is a molecule that is in a highly energetic and reactive state It is short lived as it disappears virtually as fast as it is formed. They are short lived CA 10-14s and present in very low concentrations. That is, the net rate of reaction of an active intermediate, A*, is zero.

\( r_{A^*} = \sum r_{iA} = 0 \)

The assumption that the net rate of reaction is zero is called the Pseudo Steady State Hypothesis (PSSH)

The active intermediates reside in the trough of the reaction coordinate as shown below for \(\ce{C1-C2-C3-C4}\) Zewoil.

Two reaction coordinate diagrams showing energy changes. (a) A single-step reaction converting a hydrocarbon with single bonds to one with double bonds. (b) A two-step reaction with a cyclic intermediate and activation energy (E) labeled. Both form CH₂=CH₂. Courtesy Science News, 156, 247 (1999).



Hall of Fame Reaction

The reaction

\(\ce{2NO + O2 -> 2NO2}\)

has an elementary rate law

\( r_{NO_2} = k C_{NO}^2 C_{O_2} \)

However... Look what happens to the rate as the temperature is increased.


A graph showing f_NO2 on the y-axis and temperature (T) on the x-axis. The curve decreases as temperature increases, indicating an inverse relationship.

Why does the rate law decrease with increasing temperature?

Mechanism:

\(\ce{NO + O2 -> NO3^*} \quad (1)\)

\(\ce{NO3^* -> NO + O2} \quad (2)\)

\(\ce{NO3^* + NO -> 2NO2} \quad (3)\)

\( \frac{r_{NO_2}}{2} = r_{3NO_3^*} = -k_3 C_{NO_3^*} \cdot C_{NO} = k_3 [NO_3^*][NO] \)


Pseudo Steady State Hypothesis (PSSH)

The PSSH assumes that the net rate of species A* (in this case, NO3*) is zero.

\( r_{NO_3^*} \approx 0 = k_1 (NO)(O_2) - k_2 (NO_3^*) - k_3 (NO_3^*)(NO) \)

Solving for NO3*

\( NO_3^* = \frac{k_1 [NO][O_2]}{k_2 + k_3 [NO]} \)


\( r_{NO_2} = -2r_{3NO_3^*} = 2k_3 \frac{\left[ k_1 (NO)(O_2) \right] NO}{k_2 + k_3 (NO)} \)

\( r_{NO_2} = \frac{2 k_1 k_3 (NO)^2 (O_2)}{k_2 + k_3 (NO)} \)

\( k_2 \gg k_3 (NO) \)

\( r_{NO_2} = \frac{k_1 k_3}{k_2} (NO)^2 (O_2) = \frac{A_1 A_3}{A_2} e^{\frac{E_2 - (E_1 + E_3)}{RT}} (NO)^2 (O_2) \)

\( E_2 > (E_1 + E_3) \)

This result shows why the rate decreases as temperature increases.


Enzymes

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Michaelis-Menten Kinetics    

Enzymes are protein like substances with catalytic properties. 

A 3D ribbon diagram of a protein structure with complex folding patterns and a marked black dot indicating a specific site.

Enzyme unease. [From Biochemistry, 3/E by Stryer, copywrited 1988 by Lubert Stryer.  Used with permission of W.H. Freeman and Company.] 

It provides a pathway for the substrate to proceed at a faster rate.  The substrate, S, reacts to form a product P.  

A reaction diagram showing two pathways from substrate (S) to product (P). The direct path is labeled 'Slow,' while an alternative path goes through an enzyme-substrate complex (E•S) in a lower energy state and is labeled 'Fast.'


There are six classes of enzymes (\(E\)) and only six:

1. Oxidoreductases \( AH_2 + B + E \rightarrow A + BH_2 + E \)
2. Transferases \( AB + C + E \rightarrow AC + B + E \)
3. Hydrolases \( AB + H_2O + E \rightarrow AH + BOH + E \)
4. Isomerases \( A + E \rightarrow \text{iso} - A + E \)
5. Lyases \( AB + E \rightarrow A + B + E \)
6. Ligases \( A + B + E \rightarrow AB + E \)

A given enzyme can only catalyze only one reaction.  Urea is decomposed by the enzyme urease, as shown below.

It has been proposed that an artificial kidney to remove urea from the blood could contain encapsulated enzymes and be worn externally.

\( \ce{NH2OCNH2 + UREASE -> 2NH3 + CO2 + UREASE} \)

\( \ce{S + E ->[H2O] P + E} \)

The corresponding mechanism is: 

\( E + S \xrightleftharpoons[k_2]{k_1} E \cdot S \)

\( E \cdot S + W \xrightarrow{k_3} P + E \)

Michaelis-Menten Equation

\( r_p = -r_s = \frac{V_{max} S}{K_m + S} \)


Inverting yields:

\( \frac{1}{-r_s} = \frac{1}{V_{max}} + \frac{K_m}{V_{max}} \left(\frac{1}{S}\right) \)


Types of Enzyme Inhibition

Reaction steps:

\( E + S \xrightarrow{k_1} E \cdot S \)

\( E \cdot S \xrightarrow{k_2} E + S \)

\( E \cdot S \xrightarrow{k_3} P + E \)

\( I + E \xrightarrow{k_4} E \cdot I \text{ (inactive)} \)

\( E \cdot I \xrightarrow{k_5} E + I \)


Reaction Steps:

\( E + S \xrightarrow{k_1} E \cdot S \)

\( E \cdot S \xrightarrow{k_2} E + S \)

\( E \cdot S \xrightarrow{k_3} P + E \)

\( I + E \cdot S \xrightarrow{k_4} I \cdot E \cdot S \text{ (inactive)} \)

\( I \cdot E \cdot S \xrightarrow{k_5} I + E \cdot S \)


Reaction Steps:

\( E + S \rightleftharpoons E \cdot S \)

\( E + I \rightleftharpoons I \cdot E \text{ (inactive)} \)

\( I + E \cdot S \rightleftharpoons I \cdot E \cdot S \text{ (inactive)} \)

\( S + I \cdot E \rightleftharpoons I \cdot E \cdot S \text{ (inactive)} \)

\( E \cdot S \rightarrow P + E \)


Lineweaver-Burk plot showing enzyme inhibition types. The plot has 1/V on the y-axis and 1/S on the x-axis. Lines represent different inhibition types: no inhibition, competitive (slope changes), uncompetitive (intercept changes), and noncompetitive (both slope and intercept change). Figure 9-15.


Uncompetitive Substrate Inhibition


\( E + S \xrightleftharpoons[k_2]{k_1} E \cdot S \text{ (Inactive)} \)

\( S + E \cdot S \xrightleftharpoons[k_4]{k_3} S \cdot E \cdot S \text{ (Inactive)} \)

\( E \cdot S \xrightarrow{k_5} P + E \)


The Uncompetitive Substrate Inhibition rate law is

\( r_p = \frac{V_{max} S}{K_M + S \left( 1 + \frac{S}{K_I} \right)} = \frac{K_I V_{max} S}{S^2 + K_I S + K_M K_I} \)



Side Note Methanol Poisoning
Polymath Polymath code for Alcohol Metabolism Living Example Problem. Example 7-7 in the 4th Edition.


Bioreactors

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Two-part image: (a) schematic diagram of a bacterial cell labeled with cell wall, membrane, cytoplasm, nuclear region, and ribosome, with arrows showing nutrient intake and product release; (b) microscopic photo of E. coli dividing.

Diagram illustrating microbial growth. Top: nutrients lead to cell division and product formation. Middle: schematic showing inoculum introduction and cell growth over time. Bottom: growth curve with lag phase, exponential growth, stationary phase, and death phase.

Graph of bacterial growth over time with logarithmic scale, showing lag, exponential, and stationary phases. Includes microscopic images of bacterial cultures at different time points, indicated by arrows.

Data from Laboratory of H.S. Fogler taken by P.h.D Candidate Barry Wolf. 



Rate Laws



\( r_2 = k_{\text{OBS}} \left| \frac{\mu_{\max} C_S}{K_S + C_S} \right| C_C \)

\( k_{\text{OBS}} = \left| 1 - \frac{C_P}{C_P^*} \right|^n \)

\( C_P^* \) = Where product concentration at which all metabolism ceases.


Stoichiometry

A. Yield Coefficients


\( Y_{c/s} = \frac{\text{mass of new cells formed}}{\text{mass of substrate consumed to produce new cells}}, \quad Y_{s/c} = \frac{1}{Y_{c/s}} \)

\( Y_{p/s} = \frac{\text{mass of product formed}}{\text{mass of substrate consumed to form product}} \)



B. Maintenance

\( m = \frac{\text{mass of substrate consumed for maintenance}}{\text{mass of cells} \cdot \text{time}} \)

\( -r_s = r_2 Y_{s/c} + r_d Y_{s/p} + m C_e \)




A word of caution on \( Y_{P/S} : \)

A. Growth Phase

\( -r_S = Y_{s/c} r_2 + m C_C \)

B. Stationary Phase

\( -r_{S_n} = m C_C + Y_{s_n/p} r_p \)



Mass Balances

Cell:

\( V \frac{dC_C}{dt} = v_0 C_{C_i} - v C_C + (r_2 - r_d) V \)

\( r_d = |k_n + k_{\text{ox}} C_{\text{tox}}^n| C_C \)

\( \Rightarrow \quad \text{Let } D = \frac{v_0}{V} \)

Also, \( C_{C_i} = 0 \), for most systems

Substrate:

\( V \frac{dC_S}{dt} = v_0 C_{S_i} - v C_S + r_2 V \)

\( C_S = C_{S0} \quad \text{at} \quad t = 0 \)



Polymath Setup

1.)

d(Cc)/d(t) = - D*Cc + (rg - rd)

2.)

d(Cs)/d(t) = D*(Cso - Cs) - Ysc*rg - m*Cc

3.)

d(Cp)/d(t) = - D*Cp + Ypc*rg

4.)

rg = (((1 - (Cp/Cpstar))**0.52) * mumax*(Cs/(Ks + Cs))*Cc

5.)

D = 0.2

6.)

kd = 0.01

7.)

rd = kd*CC

8.)

Cso = 250

9.)

Ypc = 5.6

10.)

m = 0.3

11.)

mumax = 0.33

12.)

Ysc = 12.5

13.)

Ks = 1.7

Polymath Screen Shots

Polymath Equations

Summary Table

Cc and Cp vs. Time

Cs vs. Time


Wash Out:

Diagram of a cylindrical reactor with an inlet (vo, Cso) and an outlet (v, Cc), volume V, and steady-state flow (v = vo).

1. Neglect Death Rate and Cell Maintenance

2. Steady State

\( 0 = -u C_C + r_2 V \)

\( D C_C = r_2 = \frac{\mu_{\max} C_S}{K_S + C_S} C_C = \mu C_C \)

\( D = \mu = \frac{\mu_{\max} C_S}{K_S + C_S} \)

\( C_S = \frac{D K_S}{\mu_{\max} - D} \)

\( C_C = Y_{C/S} [C_{S0} - C_S] = Y_{C/S} \left[ C_{S0} - \frac{D K_S}{\mu_{\max} - D} \right] \)

Graph showing concentration (Cc) decreasing as variable (Dw) increases, with a steep decline near the end.

3. Washout

\( D_W = \frac{\mu_{\max} C_{S0}}{K_S + C_{S0}} \)

Maximum Production Rate

Production Rate = \( \dot{m}_c = v_o C_C \)

Dividing by the reactor volume, \( V \), which is constant

\( \frac{\dot{m}}{V} = D C_C \)

Substituting for \( C_C \)

\( D C_C = D Y_{C/S} \left( C_{S0} - \frac{D K_S}{\mu_{\max} - D} \right) \)

Graph showing cell concentration (Cc) and production rate (Dc) as a function of dilution rate (D). The production rate reaches a maximum at Dmaxprod before declining, while cell concentration remains relatively steady before dropping at higher dilution rates. The residual substrate concentration (Cs) increases sharply after Dmaxprod.

How does this figure relate to drinking a lot of fluids when you have an infection or cold?



Pharmacokinetics

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Alcohol Metabolism

\( \text{C}_2\text{H}_5\text{OH} \xrightleftharpoons{\text{ADH}} \text{CH}_3\text{CHO} + \text{H}_2\text{O} \xrightarrow{\text{ALDH}} \text{CH}_3\text{COOH} \)

\( \text{C}_2\text{H}_5\text{OH} + \text{NAD}^+ \xrightleftharpoons{\text{ADH}} \text{CH}_3\text{CHO} + \text{H}^+ + \text{NADH} \)

\[ - r_{ADC} = \frac{\left[V_{\max}^{\text{ADH}} C_{Ac} - V_{\text{rev}}^{\text{ADH}} C_{De}\right]}{K_{M}^{\text{ADH}} + C_{Ac} + K_{\text{rev}}^{\text{ADH}} C_{De}} \]

\( \text{NAD}^+ + \text{CH}_3\text{CHO} + \text{H}_2\text{O} \xrightarrow{\text{ALDH}} \text{CH}_3\text{COOH} + \text{NADH} + \text{H} \)

\[ - r_{De} = \frac{V_{\max}^{\text{ALDH}} C_{Ac}}{K_{M}^{\text{ALDH}} + C_{Ac}} \]

Diagram of a pharmacokinetic model illustrating drug distribution in the human body. The flow starts from the stomach (Vs) to the gastrointestinal system (Vg), then to the liver (Vl), which processes the drug at a rate of 1350 ml/min. The system then distributes the drug to the central compartment (Vc = 15.3 l) and further into the muscle compartment (Vm = 22.0 l). Arrows indicate the movement of the drug between compartments, with different flow ratios.



POLYMATH results table for Example 7-7 Alcohol Metabolism, displaying calculated values of DEQ variables including initial, minimal, maximal, and final values for multiple parameters.

ODE Report (STIFF) displaying a list of differential equations entered by the user, including rate equations for variables such as Vs, Cc, Cca, Ctyd, Cta, CL, and Cga, formatted in a numbered list.

List of explicit equations entered by the user, including parameter definitions such as kd, vl, vt, Vc, Vt, Vg, VI, VmAL, Vrev, KmAL, Krev, VmaxAc, KmAc, Cso, a1, a2, Vs1, Ds, and ks, with conditional and algebraic expressions.

Drug Delivery

Diagram of a pharmacokinetic model with compartments C and P. Inputs include oral (k_A) and intravenous administration. Arrows represent rate constants: elimination (k_e), redistribution (k_R), and exchange between compartments (k_CP, k_PC).                  Pharmacokinetic graph showing drug concentration (mc) over time on a logarithmic scale. The curve is divided into a rapid distribution phase with slope -α and a slower elimination phase with slope -β.

Polymerization

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Polymers are macromolecules built up by the linking together of large numbers of much smaller molecules. The smaller molecules are called monomers and they repeat many times.

A polymer is a molecule made up of repeating structural (monomer) units.

Polymerization reaction showing two monomers, NH2RNH2 and HOOC-R'-COOH, forming a repeating polymer unit with structural units NHRNH and OCR'CO, releasing OH and water molecules.

 

Examples of Polymers

Polymerization reaction showing the addition of n(CH2=CH) to an R group, forming a repeating polymer chain with substituted groups along the backbone.

Poly (vinyl chloride)

 

Natural Polymers

Proteins
DNA/RNA
Cellulose
Fats
Starch

Synthetic Polymers

Name Structural Repeating Unit (mer) Uses
Poly (vinyl chloride) PVC structure Pipes
Polyethylene Polyethylene structure High density: Plastic cups
Low density: Sandwich bags
Polystyrene Polystyrene structure Coffee Cups
Poly (acrylic acid) Poly acrylic acid structure Superglue (Dow)
Poly (cyano acrylate) Poly cyano acrylate structure Superglue
Poly (vinyl acetate) Poly vinyl acetate structure Chewing gum
Poly (vinyl alcohol) Poly vinyl alcohol structure Shampoo/Thickener
Poly (ethylene glycol) Poly ethylene glycol structure Stealth molecule
Poly (methyl methacrylate) Poly methyl methacrylate structure Plexiglas
Poly (2-hydroxyethyl methacrylate) Poly hydroxyethyl methacrylate structure Contact Lenses
Poly (tetra fluoro ethylene) Poly tetra fluoro ethylene structure Teflon
Poly (ethylene terephthalate) Poly ethylene terephthalate structure Coke bottles
Spinable fibers

 

A. Names/Nomenclature

Polymers that are synthesized from a single monomer are named by adding the prefix poly such as polyethylene. However, a parenthesis is placed after the prefix poly when the monomer has a substituted parent name or multiword name such as poly (acrylic acid) or poly (vinyl alcohol).

Homopolymers consist of a single repeating unit. All of the above are examples of homopolymers.

 

B. Polymer structure

1. Linear

Small waveform-like line with varying peaks and dips, possibly representing a signal, function, or data trend. Linear HDPE (70-90% crystalline)

2. Stereoregularity Can Crystallize.

a.

Botactic = isotatic = same side

Chemical structure with a main horizontal backbone and four hydroxyl (OH) groups attached at regular intervals.

 

b.

Syndiotatic = alternating

Chemical structure with a horizontal backbone and five hydroxyl (OH) groups attached at different positions, some extending above and some below the backbone.

c.

Atactic = random

Chemical structure labeled 'Amorphous' with a horizontal backbone and multiple hydroxyl (OH) groups attached at different positions, some extending above and some below the backbone.

Head to head (1,2 addition)

Polymerization reaction showing monomer with repeating CH2-CH units with hydroxyl (OH) side groups polymerizing into a larger structure with multiple CH and CH2 units, each with OH functional groups attached.

 

Head to tail (1,3 addition)

Polymerization reaction of vinyl alcohol, showing a monomer unit with a CH2-CH structure and an OH side group polymerizing into a long chain structure with repeating CH, CH2, and OH functional groups.

 

3. Branched Type A: Long Branches Off Backbone

Polymer structure illustration showing a labeled 'Backbone' with a thickened central chain and irregular branching side chains.

 

Branched Type B: Short Branches Off the Backbone

Polymer structure with a central backbone chain and irregular branching side chains.

 

Branched Type C: Branches on Branches Off the Backbone

Polymer structure with a repeating CH2-CH backbone and a side group containing hydroxyl (OH) functional groups.

4. Cross linked

Polymer structure with a repeating CH2-CH backbone and a cross-linked network structure.

 

C. Copolymers

More than one repeating unit.

\( nA + nB \longrightarrow \{ A \}_n \{ B \}_n \)


For example, copolymers used to make records.

PVC - hard - irrigation pipes, hard to engrave
PVAc - easy to engrave
PVC + PVAc copolymer -> phonograph records (these are a thing of the past)

 

FIVE TYPES OF COPOLYMERS

Alternating

QSQSQS

Poly (vinyl acetate-alt-vinylchloride)

Block

QQQSSS

Poly (vinyl acetate-b-vinyl chloride)

Graph

QQQQQ
. . . . . |
. . . . . SSSS

Poly (vinyl acetate-g-vinyl chloride

Random

QSSQQQSQSSS

Poly (VAc-co-VC)

Statistical

QSSQSQQSS

 

D. What affects polymer properties

• Chemistry       Comparison of two polymer structures: one with a hydroxyl (-OH) side group and the other with a carboxyl (-COOH) side group attached to a repeating CH2-CH backbone.

• Molecular Weight (\(\overline{MW}\)) and Molecular Weight Distribution

 

Graph comparing two molecular weight distributions. Curve 1 represents a lower molecular weight (MW1), while curve 2 represents a higher molecular weight (MW2), with MW2 being greater than MW1. MW2 being greater than MW1

Weight Average Molecular Weight

 

Graph showing two molecular weight (MW) distributions. Curve 1 has a narrow peak, while curve 2 has a broader distribution. The equation MW1 = MW2 indicates that both distributions have the same average molecular weight. MW1 being greater than MW2

Molecular Weight Distribution

• Crystalinity

Amorphous Phase (Non-crystalline Phase) no order or orientation

 

Schematic representation of an entangled polymer network within an oval boundary, depicting a complex arrangement of polymer chains.

 

Tg - characteristic of amorphous state

Rubbery \( T_g \rightarrow \) glassy

Below glass transition temperature, Tg, there is a cessation of virtually all molecular motion (vibration , rotation).

 

Crystalline Phase gives an order to the structure.

 

Diagram of a polymer system with oriented chains inside an oval boundary, indicating ordered polymer alignment.

 

 

Order means crystallinity

Crystalline \( T_m \rightarrow \) liquid

Above the crystalline melting temperature, Tm, thre is no order. Fraction of total polymer that is in the crystalline state is the degree of crystallinity

 

• Cross linking

• Branching

• Tacticity

• Head to head attachment vs. head to tail attachment

 

E. Molecular Weight (MW)

1. Measurement

Membrane osmometry

Diagram of a U-shaped container with a central section labeled pi, possibly representing a fluid mechanics or physics concept.

Gel permeation chromatography

 

Diagram showing a cylindrical object with an input arrow, a mixing or reaction process, a molecular structure with black dots, and a waveform graph, possibly representing a chemical or polymer processing concept.

Viscosity

Diagram of a U-tube viscometer with a note explaining that higher molecular weight (MW) leads to a longer time to fall between the lines.

Light scattering

 

2. Calculation

Number average molecular weight \(\overline{M_n}\)

\(\overline{M_n} = \frac{\text{Total weight of polymer}}{\text{Number of moles present}} = \frac{W}{\sum N_i}\)

\(\overline{M_n} = \frac{\sum N_i M_i}{\sum N_i} = \sum y M_i\)

Weight average molecular weight \(\overline{M_w}\)

\(\overline{M_w} = \sum w_i M_i \quad \text{(Gives greater emphasis to larger molecules)}\)

\(w_i = \frac{N_i M_i}{\sum N_i M_i} = \frac{m_i}{W}\)

\(\overline{M_w} = \frac{\sum N_i M_i^2}{\sum N_i M_i}\)



Hence \(\overline{M_w}\) gives a truer picture of the average molecular weight.

Graph showing molecular weight distribution with weight fraction on the y-axis and molecular weight (MW) on the x-axis. The graph marks the number average molecular weight (Mn) and weight average molecular weight (Mw).

\( 3H_2 + CO \xrightarrow{\text{Ni-Mo-Cu}} CH_4 + H_2O \)

3. Polydispersity   

\( D = \frac{\overline{M_w}}{\overline{M_n}} \)

 

TWO TYPES OF HOMOGENEOUS POLYMERIZATION: STEP AND CHAIN

Step Polymerization. Monomer must be bifunctional. Polymerization proceeds by the reaction of two different functional groups. Monomer disappears rapidly, but molecular weight builds up slowly.

Graph showing molecular weight (MW) increasing over time (t) with an upward curve.

All species are treated as polymers. Mostly used to produce polyesters and polyamides.

Chain Polymerization. Requires an initiator. Molecular weight builds up rapidly. Growing chains require 0.0001 to 1 to 10 seconds to terminate. Have high molecular weight polymers right at the start.

Graph showing molecular weight (MW) versus time (t), with multiple curves indicating increasing polymer amount over time.

 

I. Step Polymerization

A. Functional Groups

\(-\text{OH}, -\text{COOH}, -\text{NH}_2, -\text{COCl}\)



1. Different functional groups on each end of monomer.

\(\text{H} \left[ \text{HN} - (\text{CH}_2)_5 - \text{CO} \right] \text{OH}\)

\(\text{A} \quad \quad \quad R_S \quad \quad \quad \quad \quad \text{B}\)

Structural Unit

 

 Chemical reaction equation showing polymerization process with hydroxyl (OH) and amide (NHRCO) groups forming a polymer and releasing water.

Here the structural unit is the repeating unit.

2. Same functional groups on each end. Example: diamines and diols

Two structural units \( R_{s1} \) and \( R_{s2} \)

Chemical reaction showing polymerization of amide groups, involving NHR1NH and carboxyl (C=O) functional groups, leading to the formation of a polymer with water as a byproduct.

Repeating unit = \( R_{s1} R_{s2} = R_{R} \)

 

B. Polymerization Mechanism

Monomer dimer ----> trimer ----> tetrameter ----> Pentamer ---->

\( AR_1B + AR_1B \longrightarrow AR_2B + AB \)

\( AR_1B + AR_2B \longrightarrow AR_3B + AB \)

\( AR_2B + AR_3B \longrightarrow AR_5B + AB \)

\( AR_2B + AR_4B \longrightarrow AR_6B + AB \)

Monomer \( M \)

Dimer \( M + M \xrightarrow{k_1} M_2 \quad k_1 = 20 \times 10^{-4} \text{ dm}^3/\text{mol}\cdot s \)

Trimer \( M + M_2 \xrightarrow{k_2} M_3 \quad k_2 = 15 \times 10^{-4} \text{ dm}^3/\text{mol}\cdot s \)

Tetramer \( M_3 + M_1 \xrightarrow{k_3} M_4 \quad k_3 = 7.5 \times 10^{-4} \text{ dm}^3/\text{mol}\cdot s \)

Pentamer \( M_2 + M_2 \xrightarrow{k_4} M_4 \)

\( M_2 + M_3 \xrightarrow{k_5} M_5 \)

\( M_1 + M_4 \xrightarrow{k_5} M_5 \)

Hexamer \( M_1 + M_5 \xrightarrow{k_6} M_6 \)

\( M_2 + M_4 \xrightarrow{k_6} M_6 \)

\( M_3 + M_3 \xrightarrow{k_6} M_6 \)

For i > 2

\( k_i = 7.5 \text{ dm}^3/\text{mol}\cdot s \)

 

C. Structural Units

The number of structural units equals the number of bifunctional monomers present.

1. Monomers with different functional groups - one structural unit.

Polymerization reaction equation showing the formation of a polymer from H(NHR1C)OH, with water as a byproduct.

Here the repeating unit is the structural unit.

Let p = fraction of functional groups of either A or B that have reacted.

Let M = concentration of either A or B functional groups at time t.

Let M0 be the concentration of either A or B functional groups initially

\( M = M_0 - M_0 p = M_0 (1 - p) \)

Let N = total number (concentration) of polymer molecules present at time t.

Let N0 = total number of polymer molecules initially

Let MA = number of functional groups of A at time t.

Let MA0 = number of functional groups of A initially.

\( \overline{X}_n \) = number average degree of polymerization. It is the average number of structural units per chain.

 

\( \overline{X}_n = \frac{N_0}{N} \)

\( \overline{X}_n = \frac{M_0}{M} \)

therefore

\( \overline{X}_n = \frac{1}{1 - p} \)

\( \overline{M}_n \) the number average molecular weight.

\( \overline{M}_n = \overline{X}_n \overline{M}_s + M_{eg} \)

Where \(\overline{M}_s\) is the mean molecular weight of the structural units and \(M_{eg}\) is the molecular weight of the end group.



D. Monomers with Same End Group

Polymerization reaction equation showing the formation of a polymer from HO-{R}-OH and H-{OC-R1-C-O}-H, resulting in a repeating unit made up of two different structural units with water as a byproduct. R = 100, R' = 200.

For a stoichiometric feed the number of A and B functional groups the same.

Chemical reaction equation showing ARB + BR'B → ARR'B + AB.



E. Stoichiometry Imbalance in the Feed

1. Stoichiometry Imbalance Type 1:  Monomers with thesame end group and r not equal to  1 

\( r = \frac{\text{number of A functional groups initially}}{\text{number of B functional groups initially}} = \frac{M_{A0}}{M_{B0}} \)

\( M_A = \text{number of A functional groups remaining} \)

\( M_B = \text{number of B functional groups remaining} \)

\( N = \text{Number of molecules remaining} = \frac{M_A + M_B}{2} \)

\( p = \text{fraction of A functional groups unreacted} \)

\( M_A = M_{A0}(1 - p) \)

\( M_B = M_{B0} - pM_{A0} = M_{B0} - pM_{B0} \frac{M_{A0}}{M_{B0}} = M_{B0} - p r M_{B0} = M_{B0} - p r M_{B0} = M_{B0}(1 - pr) \)

\( M_{A0} + M_{B0} = rM_{B0} + M_{B0} = (r + 1)M_{B0} \)

\( \overline{X}_n = \frac{M_{A0} + M_{B0}}{\frac{M_A + M_B}{2}} = \frac{M_{A0} + M_{B0}}{M_A + M_B} = \frac{(r + 1) M_{B0}}{M_{B0} [(1 - p) + 1 - rp]} \)

\( \overline{X}_n = \frac{r + 1}{1 + r - 2rp} \) / QED

The maximum number average chain length is greatly reduced if the initial feed is not exactly stoichiometric

If p = 1 then \( \overline{X}_n = \frac{r + 1}{1 - r} \)



2. Stoichiometry Imbalance Type 2:  Monomers with different end groups. Monofunctional Monomer Present

\( A - R - A \quad . \quad B - R - B \quad . \quad B - C \)

\( r = \frac{\text{number of ARA molecules}}{\text{number of BRB molecules} + \text{number of BC molecules}} \)

\( [A - R - A]_o = [B - R - B]_o = M_{A0} \)

\( r = \frac{M_{A0}/2}{M_{A0}/2 + M_{B0}} = \frac{M_{A0}}{M_{A0} + 2M_{B0}} \)

\( [B - C]_o = M_{B0} \)

 

3. Stoichiometry Imbalance Type 3:  Monomers with different end groups. Monofunctional Monomer Present

\( A - R - B + BC \)

\( r = \frac{N_{A0}}{N_{A0} + 2N_{B0}} \)

 

REACTION BETWEEN A DIOL (HOROH) AND A DIBASIC ACID (HOOCR1COOH)

Reaction (A) showing the formation of a repeating polymer unit from HO-{R}-OH and H-{OCR1}-COH with water as a byproduct.

Reaction (B) showing the polymerization process where HO-{ROCR1}-COH reacts with HO-{ROCR1}-COOH to form a repeating polymer unit and water as a byproduct.

Chemical reaction showing HO-R1{OH + H} reacting with O=C(R')OCR2 COH to form HO-R1-R2-CO and H2O.
Chemical reaction showing HO-{R1R2CO}-H reacting with HO-{R1R2CO}-H to form HO-{R1R2CO R1R2}-COOH and H2O.

Let

Equation defining MWA as HO-{R1R2CO}n with a carbonyl functional group.

Chemical equation representing a polymer with a carboxyl (-COOH) end group and repeating {R1R2CO} units.

Then

Chemical reaction showing an esterification process where an alcohol (-OH) reacts with a carboxyl (-COOH) group to form an ester (-COO-) and water (H2O).

Overall Reaction:

The Mechanism

Rate Law:

\( -r = k[H^+] (\sim OH)(-COOH) = -r_{\sim OH} \)



(1)

Chemical reaction showing an equilibrium between a carboxyl (-COOH) group and an acid (HA), leading to the formation of a hydroxylated (-OH) intermediate and conjugate base (A-), with forward and reverse rate constants k1 and k2.

(2)

Chemical reaction illustrating hydroxyl (-OH) addition to a carboxyl (-COOH) group, forming a new hydroxylated structure, with the release of an anion (A-) and reaction rate constant k3.

(3)

Chemical reaction showing hydroxylated carbon (-C-OH) undergoing a reaction with rate constant k4, leading to the formation of a carboxyl (-CO) group and water (H2O) as a byproduct.

\( k_1 \cdot k_2 \cdot k_4 \gg \underline{k_3} \)


Let

-- = Zigzag molecular structure representation, commonly used to depict hydrocarbon chains or polymer backbones.

~ = Curved molecular structure representation, commonly used to depict hydrocarbon chains or polymer segments.

The rate limiting step is Reaction (2)

\( -r = k_3 \left[ -\text{Q}^{+}(\text{OH})_2 \right] [\sim \text{OH}] \)


Assume Reaction (1) is essentially in equilibrium

\( \frac{\left[ -\text{C}(\text{OH})_2 (\text{A}^-) \right]}{\left[ \text{HA} \right] [\text{COOH}]} = K \)


\( r = k \left[ -\text{COOH} \right] \left[ \sim \text{OH} \right] \left[ \text{HA} \right] , \quad k = k_3 K \)

 

Case 1: The acid itself acts as a strong acid catalyst:

[HA] º  [COOH] and Stoichiometric Feed.


\(-\frac{d[-\text{COOH}]}{dt} = k[-\text{COOH}]^2 [\sim \text{OH}] = k(-\text{COOH})^3\)

\(\frac{1}{(1 - p)^2} = 2kM_o^2 t + 1\)  

Graph depicting the relationship between 1/(1-p)^2 and time, showing data fitting for less polar substances and deviation for more polar substances.

As the reaction proceeds and more ester is produced, the solution becomes less polar. As a result the uncatalyzed carboxylic acid becomes the major catalyst for the reaction, and the overall reaction order at high conversion is well described by a third order reaction (Case 1). The high conversion region is of primary importance because this region is where the high molecular weight polymers are formed.

At low conversions the solution is more polar and the proton, H+ is the more effective catalyst (Case 2) than the unionized carboxylic acid. Under these conditions, the reaction is self catalyzed and the reaction is 5/2 order.

 

Case 2: Self catalyzed but acid acts as a weak acid catalyst, not completely dissociated

[HA] =  [-COOH]

\(\text{HA} \rightleftharpoons \text{H}^+ + \text{A}^- \quad , \quad \text{H}^+ = \text{A}^-\)

\(\text{H}^+ = \sqrt{K_A (\text{HA})}\)

\(-\frac{d[-\text{COOH}]}{dt} = k_3 K K_A^{1/2} [-\text{COOH}]^{3/2} [\sim \text{OH}] = k' [-\text{COOH}]^{5/2}\)

\(-\frac{dM}{dt} = k' M^{5/2}\)

\(\frac{1}{(1 - p)^{3/2}} = \frac{3}{2} k M_0^{3/2} t + 1\)    

 

Graph illustrating the relationship between 1/(1-p)^(3/2) and time, showing data points where some fit the model while others deviate.

 

Case 3: External Acid Catalyzed H+ is constant

\(-\frac{d(-\text{COOH})}{dt} = k \left[ \frac{\text{H}^+}{k_1} \right] [-\text{COOH}][\sim \text{OH}]\)

\(\frac{1}{1 - p} = M_0 k_1 t + 1\)    

Graph showing the relationship between 1/(1-p) and time, with a slope labeled as M₀ k₁ and a region where the data does not fit the model.

 

F. Kinetics of Step Polymerization

(1)

\(\text{ARB} + \text{ARB} \longrightarrow \text{AR}_2\text{B} + \text{AB}\)

\(\text{P}_1 + \text{P}_1 \xrightarrow{k} \text{P}_2 + \text{AB}\)

k is defined wrt the reactants

\(-r_{P_1} = 2k P_1^2\)

\(r_{P_2} = \frac{-r_{P_1}}{2} = k P_1^2\)


Why 2k? Because there are two ways A and B can react (thus, 2k)

\( A - R_n - B \)

\( A - R_m - B \)

(2)

\( P_1 + P_2 \longrightarrow P_3 \)

\( -r_{2P_1} = 2kP_1P_2 \)

(3)

\( P_1 + P_3 \longrightarrow P_4 \)

\( -r_{3P_1} = 2kP_1P_3 \)

\( r_{P_1} = r_{1P_1} + r_{2P_1} + r_{3P_1} \)

\( = -2kP_1^2 - 2kP_1P_2 - 2kP_1P_3 \)

For all reactions of P1

\( r_{P_1} = -2kP_1 \sum_{j=1}^{\infty} P_j = -2kP_1 M \), where \( M = \sum_{j=1}^{\infty} P_j \)

In general for j ? 2

\( r_{P_T} = r_j = k \sum_{i=1}^{j-1} P_i P_{j-i} - 2kP_j M \)

For j = 2

\( r_2 = k \sum_{i=1}^{1} P_i P_{j-1} - 2kP_2 M = kP_1^2 - 2kP_2 M \) \quad / QED

Mole balance on polymer of length j, in terms of the concentration Pj in a batch system

\( r_j = r_{P_j} = \frac{dP_j}{dt} \)

\( r_j = k \sum_{i=1}^{j-1} P_i P_{j-i} - 2kP_j M \)

then

\( \frac{dP_j}{dt} = k \sum_{i=1}^{j-1} P_i P_{j-i} - 2kP_j M \)

\( \frac{dM}{dt} = -kM^2 \) , \( \quad t = 0 \quad M = M_o \)   

\( M = \frac{M_o}{1 + M_o k t} \)

 

\( P_1 = M_o \left( \frac{1}{1 + k M_o t} \right)^2 \)

At t = 0, P2 = 0

\( P_2 = M_o \left( \frac{1}{1 + M_o k t} \right)^2 \left( \frac{M_o k t}{1 + M_o k t} \right) \)

If we proceed further it can be shown that

\( P_j = M_o \left( \frac{1}{1 + M_o k t} \right)^2 \left( \frac{M_o k t}{1 + M_o k t} \right)^{j-1} \)

\( P_j = M_o (1 - p)^2 (p)^{j-1} \)

\( p = \frac{M_o - M}{M_o} \)

Total number of polymer molecules (i.e. functional groups of either A or B) = \( \sum P_j = M \)

Mole fraction \( y_j = \frac{P_j}{M} = \frac{P_j}{M_o (1 - p)} \)

\( y_j = (1 - p) p^{j-1} \)

This is the Flory Distribution for the mole fraction of molecules with chain length j.

The weight fraction is just

\( P_j = M_o (1 - p)^2 p^{j-1} \)

\( w_{P_j} = (MW_s)_j M_o (1 - p)^2 p^{j-1} \)

W = total weight = \( MW_s M_o \)

\( w_j = \frac{w_{P_j}}{W} = \frac{w_{P_j}}{MW_s M_o} = j(1 - p)^2 p^{j-1} \)

 

G. Flory Distribution-Probability Approach

Rule: The probability of several events occurring successively in a particular way equals the product of the probabilities that each event happens that way.

 P = probability that an A group will has reacted

(1-P) = probability group has not reacted.

A - R - B

HO - R C OO - H

Polymer structure with repeating ester units labeled as RCO, ending in an unreacted hydroxyl group, annotated with 'Need this unreacted'.

 

Probability of 1st link is P

 

Probability of 2nd link is P

 

Probability of A or B unreacted = (1 - P)

  

\( \text{Probability of Forming an } x\text{-mer} = \left( \text{Probability of } x-1 \text{ ester linkage} \right) \times \left( \text{Probability of unreacted } x\text{-group} \right) \)

\( = P^{x-1} (1-P) \)

\( M_x = M P^{x-1} (1-P) \)

Equation for Mx showing M times P raised to (x-1) times (1-P), with annotations explaining 'number of x-mers' and 'total number of molecules of all sizes (changes with conversion)'.

Mo = number of functional groups initially (no. of molecules)

M = number of functional groups remaining

\( p = \frac{M_O - M}{M_O} \)

\( M = M_O (1 - p) \)

\( M_x = M_O p^{x-1} (1 - p)^2 \Rightarrow \)

Number distribution function.

\( y_x = \frac{M_x}{M_O} = p^{x-1} (1 - p) \)

\( w_x = x M_{Ws} \cdot M_x \)

\( = M_O \left[ x (1 - p)^2 p^{x-1} \right] M_{Ws} \)

Weight distribution function

\( w_x = \frac{w_x}{M_O M_{Ws}} = x(1 - p)^2 p^{x-1} \)

 

Graph showing yi versus i with two decreasing curves labeled p = 0.96 and p = 0.995.       Graph showing wi versus i with two peaks labeled p = 0.96 and p = 0.995.

On a number average basis there will always be more monomer than polymer.


 

II. Chain Polymerization

A. Free Radical

Example: Polyethylene

\( \text{I}-\text{CH}_2(\text{CH}_2)_n\text{CH}_2\bullet + \text{H}_2\text{C}=\text{CH}_2 \longrightarrow \text{I}-\text{CH}_2(\text{CH}_2)_{n+1}\text{CH}_2\bullet \)

Linear addition

Chemical structure showing a polymer chain with a radical site at the end. Chemical reaction showing the addition of an ethylene monomer (+H2C=CH2) to a growing polymer chain. Radical polymerization intermediate with a growing polymer chain ending in an ethylene unit (H2C=CH2) and a radical site.

Back biting

 

Linear polymer chain segment terminating in a radical site.     \(\Rightarrow\)     Polymer chain loop with radical site, indicating hydrogen abstraction (bite).  \(\Rightarrow\) Illustration of a free radical represented by a black dot on a polymer chain.

\(\text{HC}_2 = \text{CH}_2 +\)  Illustration of a polymer chain with a central free radical represented by a black dot.   \(\Rightarrow\)   Illustration of a polymer chain with a radical or functional group extending from the main chain.  \(\Rightarrow\)  Structural diagram illustrating a polymer backbone with branching points.

Branched Polyethylene resulting low density (0.92)

 

B. Cationic Polymerization

\(\text{BF}_3 + \text{H}_2\text{O} \longrightarrow \text{HOBF}_3^- + \text{H}^+\)

\[ \begin{array}{c} H^+ + & CH_2 = CH_2 \longrightarrow CH_3 - CH_2^+ \\ \end{array} \]

\[ \begin{array}{c} CH_3 - CH_2^+ + H_2C = CH_2 \longrightarrow CH_3CH_2 CH_2^+ , \text{etc.} \\ \end{array} \]

C. Anionic Polymerization

\(\text{A} \xrightleftharpoons{} \text{A}^- + \text{B}^+\)

\(\text{A}^- + \text{M} \longrightarrow R_1'\)

\(R_1' + \text{M} \longrightarrow R_2', \text{ etc.}\)

D. Ziegler-Natta Polymerization

Ziegler-Natta Catalyst \([\text{TiCl}_4\text{Al}(\text{CH}_2\text{CH}_3)_3]\)

Diagram of a catalyst particle showing an active site and diffusion of H2C=CH2 through a pore.

Steps in Polymer Chain Growth

Diagram illustrating ethylene polymerization at an active site with restricted branching due to a narrow pore.

(4) Desorption from active site

\(\Rightarrow\)    Diagram showing an active site with polymer growth restriction.   +   Graphical representation of a polymer structure.

to produce linear polymer: Eq. High Density Polyethylene (0.98) (HDPE)

Chain polymerizations require an initiator.


FREE RADICAL POLYMERIZATION

1. The Reaction

INITIATION

\(\text{I}_2 \xrightarrow{k_0} 2\text{I} \cdot \quad (\text{slow})\)

This reaction produces the formation of the Primary Radical

\(\text{I} \cdot + \text{M} \longrightarrow \text{R}_1 \cdot \quad (\text{fast})\)

PROPAGATION

\(\text{R}_1 \cdot + \text{M} \longrightarrow \text{R}_2 \cdot\)

\(\text{R}_{j-1} \cdot + \text{M} \longrightarrow \text{R}_j \cdot\)

TERMINATION

Transfer

To solvent

\(\text{R}_i \cdot + \text{S} \longrightarrow \text{P}_i + \text{S} \cdot\)

To monomer

\(\text{R}_i \cdot + \text{M} \longrightarrow \text{P}_i + \text{R}_1 \cdot\)

To chain transfer agent

\(\text{R}_i \cdot + \text{C} \longrightarrow \text{P}_i + \text{C} \cdot\)

To initiator

\(\text{R}_j \cdot + \text{I}_2 \longrightarrow \text{P}_j + \text{I} \cdot\)

Addition

\(\text{R}_j \cdot + \text{R}_k \cdot \longrightarrow \text{P}_{j+k}\)

Disproportionation

\(\text{R}_j \cdot + \text{R}_k \cdot \longrightarrow \text{P}_j + \text{P}_K\)

MORE ABOUT INITIATION

Types of initiators, homiletic, photo

\(\text{I}_2 \xrightarrow{k_o} 2\text{I}\)

\(\text{I} + \text{M} \xrightarrow{k_1} \text{R}_1\)

\(\left\{ \begin{array}{l} - r_{I_2} = k_o (\text{I}_2) \\ r_I = 2f k_o \text{I}_2 \end{array} \right.\)

\(r_i = r_{R_1} = k_i (\text{I}) (\text{M})\)


Typical Initiators for Homolytic Dissociation

\(\text{I}_2 \rightarrow 2\text{I}\)

 

Temperature Range

Initiator

(1)

50-70 \(^\circ \text{C}\)

Azobisisobutyranitride (ABIN)

Chemical reaction showing the decomposition of an organic peroxide into radicals.

T 50° 70° 100°
\( t_{1/2} \) 74 hr. 4.8 hr. 7.2 min.

 

(2)

70-90 \(^\circ \text{C}\)

Acetyl Peroxide

Chemical reaction showing the decomposition of an organic peroxide. The structure on the left consists of two acetyl groups (CH₃-C=O) connected by a peroxide (-O-O-) bond. The reaction produces two acetoxy (CH₃-C=O-O•) radicals, indicated by a dot next to the oxygen atom on the right side of the equation

 

(3)

80-95 \(^\circ \text{C}\)

Benzyl Peroxide

Chemical reaction depicting the decomposition of a benzoyl peroxide molecule. The structure on the left consists of two benzoyl groups (ϕ-C=O) connected by a peroxide (-O-O-) bond. The reaction produces two benzoyloxy (ϕ-C=O-O•) radicals, indicated by a dot next to the oxygen atom on the right side of the equation.


Kinetics

\(\frac{dI_2}{dt} = -k_o (I_2)\)

\(I_2 = I_{2o} e^{-k_o t}\)

\(\begin{array}{c} 10^{-2} \text{/s} < k_o < 10^{-6} \text{/s} \\ 25 \text{ kcal/mol} < E_a < 40 \text{ kcal/mol} \end{array}\)


Initiator Efficiency "f"

f = fraction of radicals produced in the homolysis reaction that initiate polymer chains. It is a measure of waste of initiator.

 

How to determine f experimentally

  1. In AIBN measure N2 evolution compare number of radicals produced with number of polymer molecules obtained.
  2. Tag initiator 14C or 35S
  3. Use scavengers - to stop growth.

Graph showing the effect of monomer concentration (M in mol/dm³) on the probability factor (f). The curve starts at a low value around 0.1 and increases rapidly before leveling off at higher concentrations. A label notes that at low monomer concentrations (10⁻³ to 10⁻² mol/dm³), Radical-Radical reactions are more probable than Radical-Monomer reactions.

 


2. Free Radical Polymerization Kinetics

INITIATION

PSSH applied to initiator

  (1)

\( I_2 \rightarrow 2I \)

\( r_{1I} = 2f k_o (I_2) \)

  (2)

\( I + M \rightarrow R_1 \)

\( r_{2I} = -k_1 (I)(M) \)

     

\( r_{\text{1Net}} = 0 = 2f k_o (I_2) - k_1 (I)(M) \)

     

\( (I) = \frac{2f k_o I_2}{M k_1} \)

PROPAGATION

\( R_j + M \xrightarrow{k_P} R_{j+1} \)

\( -r_j = k_P M R_j \)

For all radicals the total rate of propagation

\( R_P = \sum (-r_j) = k_P M \sum R_j = k_P M R^* \)

\( R^* \) = total concentration of radicals (R1 + R2 + R3 . . . Rn)

Monomer balance

\( - r_m = r_1 + k_p M \sum R_j = k_i MI + k_p MR^* \)

Long Chain Approximation (LCA)

\( \frac{r_1}{R_p} \ll 1 \)

The rate of disappearance of monomer, -rm,

\( - r_m = k_p M R^* \)

\( \boxed{10^2 \text{ mol/dm}^3 \cdot s < k_p < 10^4 \text{ mol/dm}^3 \cdot s} \)


TERMINATION

1. Chain transfer

A.

To monomer

 

\( R_j + M \xrightarrow{k_M} P_j + R_1 \)

\( - r_{jm} = k_{tm} M R_j \)

 

Total rate of transfer for all radicals

 

\( r_{tm} = k_{tm} M R^* \)

 

B.

To solvent

 

\( R_j + S \xrightarrow{k_M} P_j + S \bullet \)

\( -r_{js} = k_{ts} M R_j \)

 

\( \boxed{r_{ts} = k_{ts} M R^*} \)

 

C.

Transfer to a chain transfer agent

 

\( R_j + C \xrightarrow{} P_j + C \bullet \)

\( -r_j = k_{tc} M P_j \)

 

\( \boxed{r_{tc} = k_{tc} M R^*} \)

 

D.

Transfer to initiator

 

\( R_j + I_2 \xrightarrow{} P_j + I \bullet \)

\( -r_{jI} = k_{tI} (I_2) R_j \)

 

\( \boxed{r_{tI} = k_{tI} (I_2) R^*} \)

 

2. Dispropriation Termination

   

\( R_j + R_k \xrightarrow{} P_j + P_k \)

\( -r_{tjk} = k_{td} R_j R_k \)

 

\( \boxed{-r_{tkj} = k_{td} R_j R_k} \)

 

Disproportionation

Define kd wrt reactants

 

\( R_1 + R_1 \xrightarrow{} P_1 + P_1 \)

\( r_{R_1} = k_d R_1^2 \)

i.e.

\( 2R_1 \xrightarrow{} 2P_1 \)

\( \frac{r_{R_2}}{2} = \frac{-r_{R_1}}{2} , \quad r_{P_1} = -r_{R_1} \)

 

\( R_1 + R_2 \xrightarrow{} P_1 + P_2 \)

\( R_1 + R_3 \xrightarrow{} P_1 + P_3 \)

\( R_2 + R_2 \xrightarrow{} P_2 + P_2 \)

\( R_2 + R_3 \xrightarrow{} P_2 + P_3 \)

 
 

\( r_{p_1,net} = r_{p_1,1} + r_{p_1,2} + r_{p_1,3} = k_d R_1^2 + k_d R_1 R_2 + k_d R_1 R_3 \)

\( = -k_d R_1 \sum R_j = k_d R_1 (R^*) \)

\( r_{p_2} = k_d R_1 R_2 + k_d R_2^2 + k_d R_2 R_3 + \dots \)

\( = k_d R_2 (R^*) \)

\( \sum r_{p_j} = k_d \sum R_j (R^*) = k_d (R^*)^2 \)

Net rate of termination of all radicals by dispropriation. For every dead polymer molecule that is formed, one live polymer radical is lost.

\( r_{tp} = \sum_{j=1}^{\infty} r_{pj} = -r_{td} = k_d (R^*)^2 = R_{td} \)

\( 10^6 \, \text{mol/dm}^3 \cdot s < k_d < 10^8 \, \text{mol/dm}^3 \cdot s \)


3. Addition Termination

\( R_j + R_k \longrightarrow P_{j+k} \quad \quad -r_{tjk} = k_a R_j R_k \)

where ka is defined wrt to the reactant.

The net rate of termination of j radicals will all the Rk radical (k = 1, 2, ?)

\( -r_{tj} = \sum_{k=1}^{n} -r_{tjk} \)

\( -r_{tj} = k_a R_j \left[ R_1 + R_2 + R_3 + \dots R_j + \dots \right] \)

\( = k_a R_j \sum R_j = k_a R_j R^* \)

The net rate of termination of all radicals is

\( R_t = \sum_{1}^{n} -r_{tj} = k_a \sum R_j R^* = k_a \left( R^* \right)^2 \)

 

PSSH Applied to All Free Radicals \( (R_{ta} = R_{ta}) \)

\( \sum r_j = r_1 - R_t = k_i (I) (M) - k_t (R^*)^2 = 0 \)

\( R^* = \sqrt{\frac{k_i (I) (M)}{k_t}} \)

Recall

\( k_i (I)(M) = 2k_o f(I_2) \)

\( R^* = \sqrt{\frac{2k_o f(I_2)}{k_t}} \)

Example  Termination by the Initiator Primary Radicals, I

\( R_j + I \xrightarrow{k_u} P_j + I \)

\( r_t = k_t (R^*) (I) \)

\( r_p = k_p [M] R^* \)

\( r_i = k_i [M] (I) \)

\( r_t = r_i \)

\( R^* = \frac{k_i M}{k_t I} = \frac{k_i}{k_t I} \)

\( r_p = \frac{k_p k_i M^2}{k_t I} \)

Independent of Initiator Concentration

\( \ln \frac{M}{M_0} = \left( \frac{8 f k_p^2 I_{20}}{k_0 k_t} \right)^{1/2} \left[ \exp \left( \frac{-k_0 t}{2} \right) - 1 \right] \)


\( t \longrightarrow \infty \)

\( \ln \frac{M_0}{M_{\infty}} = \left( \frac{8 k_p^2 I_{20} f}{k_0 k_t} \right)^{1/2} \)

\( \ln \frac{1}{1 - p_{\infty}} = \left( \frac{8 k_p I_{20} f}{k_0 k_t} \right)^{1/2} \)

Graph showing the natural logarithm of the ratio of initial monomer concentration (M₀) to monomer concentration (M) as a function of time (t). The curve starts at a low value and increases before leveling off, with a dashed line indicating an upper limit. An equation, (8fk_pI_2₀f / k₀k_t)^(1/2), is labeled at the top of the graph.

\( \ln (1 - p) = -\ln (1 - p_{\infty}) e^{\left[ \frac{-k_0}{2} - 1 \right]} \)

\( -\ln \left[ 1 - \frac{\ln (1 - p)}{\ln (1 - p_{\infty})} \right] = \frac{k_0}{2} t \)

Dead ended polymerization occurs when the initiator concentration decreases to such a low value, the half life of the polymer chains approximates half life of initiator

Graph plotting -ln[1 - (ln(1 - p) / ln(1 - p∞))] against time (t) in hours. Two linear trends are shown, one labeled 80°C with a steeper slope and the other labeled 60°C with a gentler slope, indicating temperature-dependent reaction kinetics.

\( -\ln \left[ 1 - \frac{\ln(1 - p)}{\ln(1 - p_{\infty})} \right] \)

Polymerization of Isoprene initiated by azobisisolulyronitride.

Kinetic Chain Length

The kinetic chain length v is the average number of monomer molecules consumed (polymerized) per radial that initiates a polymer chain.

\( v = \frac{\text{rate of radical propagation}}{\text{rate of initiation}} \)

\( v = \frac{R_p}{R_i} = \frac{R_p}{R_t}, \quad (i.e. \ R_i = R_t) \)

\( \overline{X_n} = 2v \)     termination by combination (addition)

\( \overline{X_n} = v \)     termination by disproportionation

Chain Transfer

\( \overline{X_n} = \frac{R_p}{R_t + k_{tr,M} (R^*) [M] + k_{tr,S} [S] (R^*) + k_{tr,I} [I_2]} \)

\( R_p = k_p R^* M \)

In Principles of Polymerization 3/e by George Odian, the definition of Rt, the factor of 2 is incorrect but does not matter because it cancels out since Rt is dived by 2 in the denominator in later equations. Also note Eqn. (3-118a) in Odians is altogether incorrect.

Let the transfer coefficient be defined by

\( C_M = \frac{k_{tr,M}}{k_P}, \quad C_S = \frac{k_{tr,S}}{k_P}, \quad \text{and} \quad C_I = \frac{k_{tr,I}}{k_P} \)

\( \frac{1}{\overline{X_n}} = \frac{R_t}{R_p} + C_M + C_S \frac{S}{M} + C_I \frac{I_2}{M} \)

Term (1)

\( \frac{R_t}{R_p} = \frac{k_t (R^*)^2}{k_P R^* M} = \frac{k_t (k_P R^* M) R^*}{[k_P R^* M] k_P M} \)

Canceling terms

\( \frac{R_t}{R_p} = \frac{k_t R_p}{k_p^2 M^2} \)

Term (4)

\( \frac{I_2}{M} = \frac{?}{M} \)

\( (R^*)^2 = \frac{2 k_o I_{2f}}{k_t} \)

Solving for I2

\( I_2 = k_t \left( \frac{(R^*)^2}{2 k_o f} \right) \cdot \left( \frac{(M k_p)^2}{(M k_p)^2} \right) = \frac{k_t R_p^2}{2 f k_o k_p^2 M^2} \)

\( \frac{I_2}{M} = \frac{k_t R_p^2}{2 k_o f k_p^2 (M^3)} \)

The Mayo-Walling Equation

\( \frac{1}{\overline{X_n}} = \frac{k_t R_p}{k_p [M^2]} + C_M + C_S \frac{S}{M} + C_I \frac{k_t R_p^2}{2 k_p^2 k_o f [M^3]} \)

Let's neglect the term \( \left[ C_S \frac{S}{M} \right] \)

Graph of 1/Xn versus Rp. The graph shows different slopes for different initiators and different CI values. The slope is represented by kt / (kp[M]^2). The intercept is labeled as CM.

For styrene

In benzyl peroxide

CM = 0.00006

CI = 0.055

In benzene

CS = 2.3 ´ 10?6

In Butyl mercaptan

CS = 21.1

Increasing the initiator concentration decreases \( \overline{X_n} \)

Increasing the monomer concentration increases \( \overline{X_n} \)

Further determination of Rate Constant

\( \frac{dM}{dt} = \alpha M I_2^{\frac{1}{2}} \)

1. Dilatometry

Diagram illustrating volume charge, showing a container partially filled with a shaded substance and an open section at the top.   Volume charge

2. Spectroscopically measure I2(t) and M(t)

Graph showing a decreasing trend of I2 over time, representing a decay-like behavior.               Graph showing a decreasing trend of M over time, indicating a decay-like behavior.

B. Batch - Method of Initial Rates

A graph with M on the vertical axis and t on the horizontal axis, showing a downward-curving line. A tangent line is drawn at a point on the curve, with the slope labeled as Slope = Rp0.

Many experiments

\( R_{P0} = \alpha I_{o}^{1/2} M_{o} \)

A graph with Rp0 on the vertical axis and I₀^1/2 M₀ on the horizontal axis, showing a straight line with a labeled slope. The slope is given as α = kₚ(2f k₀ / kₚ)^1/2.

Steady State Measurement

CSTR Diagram of a Continuous Stirred Tank Reactor (CSTR) with an inlet stream labeled v₀ / M₀ and an outlet stream labeled M.

\( v_o M_o - v M + R_p V = 0 \)

\( v \approx v_o \)

\( R_p = \frac{v_o}{V} [M_o - M] \)

\( R_p = \alpha I_2^{\frac{1}{2}} M \)

Graph of Rₚ versus time with a straight-line trend indicating a slope of α.

\( I_{\text{out}}^{\frac{1}{2}} M_{\text{out}} \)

No Chain Transfer

\( \overline{X_n} = \frac{k_p}{\left(2 f k_o k_t\right)^{1/2}} \frac{M_{\text{out}}}{I_{2\text{out}}^{1/2}} = \frac{\beta M_{\text{out}}}{\left(I_{2\text{out}}\right)^{1/2}} \)

Graph of X̄ₙ versus M_out / I_out^(1/2) with a straight-line trend.

\( \alpha \times \beta = \frac{k_p}{k_t^{1/2}} \)

Determining Chain transfer Constants

A. Only transfer to chain transfer agent S

\( X_n = \frac{R_p}{R_t + R_s} \)

\( \frac{1}{X_n} = \frac{R_t}{R_p} + \frac{R_s}{R_p} \)

\( = \frac{k R^*}{k_p M} + \frac{k_{\text{tr},S} S}{k_p M} \)

\( \frac{1}{X_n} = \frac{k_t R^*}{k_p M} + \frac{k_{\text{tr},S} S}{k_p M} = \frac{k_t}{k_p} \left[ \frac{2 k_o I_2}{k_t} \right]^{1/2} \frac{1}{M} + C_s \frac{S}{M} \)

Hold M and I constant, vary S

Graph of 1/X̄ₙ versus (S/M) with a straight-line trend. The slope is labeled as Cₛ/M, and the intercept is given by (2fk₀kᵢ)^(1/2) / kₚM.

B. Transfer to monomer, initiation and a chain transfer agent

\( \frac{1}{X_n} = \frac{(2 f k_o k_t I_2)^{1/2}}{k_p M} + C_s \frac{S}{M} + C_I \frac{I_2}{M} + C_M \)

\( = \left[ \frac{(2 f k_o k_t I_2)^{1/2}}{k_p} + C_s S + C_I I_2 \right] \frac{1}{M} + C_M \)

Hold I and S constant, vary M

Graph of 1/X̄ₙ versus 1/M with a straight-line trend. The slope is labeled as [ ] = S₁, and the intercept is labeled as Cₘ.

Change I and repeat, the intercept will be the same but slope will be different, S2. Change S and repeat S3. Three equations and 3 unknowns. Could also use regression.

Transfer Constants

A. To Monomer

0.00005 < CM < .0015

CM is generally small, however chain transfer to monomer for vinyl chloride is sufficiently high to limit the molecular weight so that the maximum molecular weight of PVC is 50,000 to 500,000.

B. To Initiator

CI is a function of both the initiator and the reaction

0.0008 < CI < 0.3

Peroxides are usually the strongest chain transfer agents.

C. To Chain Transfer Agent

\( \frac{1}{X_n} = \frac{k_p R_p}{k_p^2 [M]^2} + C_M + C_I \frac{k_p R_p^2}{k_p^2 f k_d [M]^3} + C_s \frac{S}{M} \)

\( \frac{1}{X_n} = \frac{1}{X_{no}} + C_s \frac{S}{M} \)

For styrene

0.000002 < CS < 21

(Benzene) < CS < (n Butyl mercaptan)

Graph of (10⁵ / X̄ₙ) versus [S] / [M] with three labeled trend lines: C₂H₅φ, CH₃φ, and OH, increasing in slope.

Chain Transfer to Polymer, CP

Chain transfer to polymer produces branched polymers.

It is not important in determining CI, CM and CS because they are determined at low conversion.

CP involves the determination of the number of branches produced relative to the number of polymer molecules polymerized.

CP is the order of 10?4

The branching density, r , is the number of branches per monomer molecule polymerized.

\( \rho = C_p \left[ \frac{1}{p} \ln \frac{1}{1 - p} - 1 \right] \)

For CP = 10?4 and 80% conversion, there will be 1.0 branches per 104 monomer units polymerized. There is one branch for every 4,000 to 10,000 monomer units and for a polymer molecular weight of 105 ? 106 this corresponds to 1 polymer chain in 10 containing a branch.

Polyethylene

1. Short branches (less than 7 carbon atoms)

Formed by backbiting. Short branches out number the long branches by a fact of 20-50. They affect crystallinity giving maximum crystallinity of 60-70%.

2. Long branches ? formed by normal chain transfer to polymer.

Energetics (Free Radical)

\(\text{Initiation} \quad k_o = A_o e^{-\frac{E_o}{RT}} \quad 110 < E_o < 160 \quad \text{kJ/mol} \)

\(\text{Propagation} \quad k_p = A_p e^{-\frac{E_p}{RT}} \quad 15 < E_p < 40 \quad \text{kJ/mol} \)

\(\text{Termination} \quad k_t = A_t e^{-\frac{E_t}{RT}} \quad 2 < E_t < 20 \quad \text{kJ/mol} \)

\(\text{Transfer} \quad k_{tr} = A_{tr} e^{-\frac{E_{tr}}{RT}} \quad 40 < E_{tr} < 80 \quad \text{kJ/mol} \)

\( R_p \sim k_o^{1/2} k_p / k_t^{1/2} \)

\(\frac{d \ln (R_p)}{dT} \sim \left[ \frac{(2E_p + E_o) - E_t}{2RT^2} \right] \)

\( E_o > E_p > E_t \)

\(\frac{d \ln R_p}{dT} \text{ is } +, \quad \therefore R_p \uparrow \text{ as } T \uparrow \)

\(\bar{X}_n \sim k_p / (k_o k_t)^{1/2} \)

\(\frac{d \ln \bar{X}_n}{dT} = \left[ \frac{2E_p - (E_o + E_t)}{2RT^2} \right] \)

\(\therefore \bar{X}_n \downarrow \text{ as } T \uparrow \)

\(\frac{d \ln C}{dT} = \frac{E_{tr} - E_p}{RT^2}, \quad \text{normally } E_{tr} > E_p \)

Therefore chain transfer becomes more significant as temperature increases!!!

Chain Polymerization

Ionic Polymerization

Cationic A wavy line with a circled plus sign at the right end.

Used for monomers with electron releasing substituents

\( M_n A \rightleftharpoons M_n^+ A^- \rightleftharpoons M_n^+ \parallel A^- \rightleftharpoons M_n^+ + A^- \)

(a) (b) (c) (d)

e.g. alkoxy, 1,1?dealky

(a) covalent species, (b) tight ion pair, (c) loose ion pair, (d) free and highly solvated ion

Anionic A wavy line with a circled minus sign at the right end.

Used with monomers possessing electron withdrawing groups, e.g. nitride, carboxyl.

\( M_n A \rightleftharpoons M_n A^+ \rightleftharpoons M_n^- \parallel A^+ \rightleftharpoons M_n + A^+ \)

Anionic

High molecular weight. No chain-chain termination.

Initiation

Alkyllithium used because soluble in hydrocarbon solvents.

\( C_4H_9Li + CH_2 = CHY \rightarrow C_4H_9 - CH_2 - CYH \ :^- (Li^+) \)

Chemical reaction showing the reaction of C4H9Li with CH2=CHY, resulting in the formation of C4H9-CH2-C:(Li+), where C is bonded to Y and H.

Potassium amide

\( KNH_2 \xrightleftharpoons{K_e} H_2N:^− + K^+ \)

\( AB \xrightleftharpoons{} A^- + B^+ \)

Chemical reaction showing the reaction of H2N:- with φCH=CH2, resulting in the formation of H2N-CH2-C:-, where C is bonded to φ and H.

\( A^- + M \rightarrow R_1 \)

\( R_i = k_i [H_2N:^−][M] = \frac{k_i K [K_e H_2N][M]}{[K^+]} \)

Propagation

No effective termination - complete consumption of monomer to form living polymers.

\( H_2N = R_n^- + M \rightarrow H_2N - M_n M^- \)

\( R_n^- + M \rightarrow R_{n+1}^- \)

\( R_p = k_p [R_n^-][M] \)

Termination by:

a. Impurities

Moisture

Chemical reaction showing the reaction of a polymer chain with CH2-C:- (where C is bonded to φ and H) and H2O, resulting in a polymer chain with CH2-CH bonded to two φ groups and OH- as a byproduct.

\( R_{trH_2O} = k [R^-][H_2O] \)

b.  Deliberate addition of chain transfer agent

c.  Spontaneous

Hydride elimination, i.e.

Chemical reaction showing a polymer chain with CH2-CHφCH2-C-H (where C is bonded to Na+) transforming into a polymer chain with CH2-CHφCH=CHO along with H:- and Na+ as byproducts.

Comparison with free radical polymerization

Free Radical:  \( R_P = k_P [M][R^*] \)

Concentration of radicals is 10?9 to 10?7 mol/dm3

Anionic:  \( R_P = k_P^{app} [M][M^-] \)

Concentration of propagation anions is 10?4 to 10?2 mol/dm3

In hydrocarbon solvents \( k_P^{\text{app}} \) is 10-100 times smaller than kP

In either solvents \( k_P^{\text{app}} \) is 10-100 times larger than kP

   

Benzene

Tetrahydrofuran

1,2-Dimethoxyethane

  \( k_P^{\text{app}} \)

2

550

3,800

Other values are given in Odian p.412

Why do the rates of polymerization vary by several orders of magnitude in different solvents?

Kinetics of Ion/Ion Pair Initiation/Polymerization

Initiation

\( A^- (B^+) \rightleftharpoons A^- + B^+ \quad \text{ion/ion pair equilibrium} \)

\( A^- + M \xrightarrow{k_F} AM^- \quad \text{ion initiation} \)

\( AM_n^- + M \rightarrow AM_{n+1}^- \quad \text{ion propagation} \)

\( A^- (B^+) + M \xrightarrow{k_A^\pm} AM^- (B^+) \quad \text{ion pair initiation} \)

\( A^- (B^+) M_n^- + M \rightarrow A^- (B^+) M_{n+1}^- \quad \text{ion pair propagation} \)

Summing over all radicals

\( R_P = k_P^- [A^-][M] + k_P^\pm [A^- (B^+)][M] \)

where \( [A^-] \) is the concentration of \( [A^-] \) and all radicals initiated with \( [A^-] \) and \( \left[ A^- (B^+) \right] \) is the concentration of \( \left[ A^- (B^+) \right] \) and radicals initiated with \( \left[ A^- (B^+) \right] \)

We assume the ion and the ion pair are in equilibrium with the "salt."

\( K = \frac{\left[ A^- B^+ \right]}{\left[ A^- (B^+) \right]} \)

\( \left[ A^- \right] = \left[ B^+ \right] \)

\( \therefore \left[ A^- \right] = \left( K \left[ A^- (B^+) \right] \right)^{1/2} \)

Let \( [R^-] \) be the total concentration of all types of anionic living propagating centers.

\(\left[ R^- \right] = \left[ A^- \right] + \left[ A^- \left( B^+ \right) \right] = I_o\)

where Io is the total amount of initiator added.

\( I_o = \left[ A^- \right] + \left[ A^- \left( B^+ \right) \right] \)

\( \left[ A^- \left( B^+ \right) \right] = I_o - \left[ A^- \right] \)

\( R_p = k_p \left[ A^- \right] M + k_p^{\pm} \left[ I_o - \left[ A^- \right] \right] M \)

\( = k_p^{\pm} (I_o) M + \left( k_p^- - k_p^{\pm} \right) \left[ A^- \right] M \)

For small degrees of dissociation

\( \left[ A^- \left( B^+ \right) \right] \cong I_o \)

\( \left[ A^- \right] = \left[ K \left[ A^- \left( B^+ \right) \right] \right]^{1/2} = \left( K I_o \right)^{1/2} \)

\( R_p = \left( k_p^{\pm} I_o + \left( k_p^- - k_p^{\pm} \right) \left( I_o k \right)^{1/2} \right) M \)

\( R_p = k_{\text{app}} I_o M \)

\( R_p = k_{\text{app}} I_o M \)

\( k_{\text{app}} = k_p^{\pm} + \frac{\left( k_p^- - k_p^{\pm} \right) K}{I_o^{1/2}} \)

\( R^- = \sum R_j^- = I_o \)

Graph of kapp (apparent rate constant) versus a variable on the x-axis with units (dm³/mol•s). The equation (1/T₀)^(1/2) = [R⁻T]^(1/2) is displayed below the graph.

\( k_p^- \approx 5 \times 10^4 \)

\( k_p^{\pm} \approx 80 \)

Differ by a factor of \( 10^3 \)

If \( K \sim 10^{28} \) and

\( \sqrt{K} \sim 10^{-4} \)

then

\( k_{\text{app}} = 80 + \frac{50,000 \times 10^{-4}}{I_o^{1/2}} \)

\( k_{\text{app}} = 80 + \frac{5}{I_o^{1/2}} \)

If \( K \sim 10^{26} \) then

\( k_{\text{app}} = 80 + \frac{50}{I_o^{1/2}} = 80 + \frac{50}{R^{-1/2}} \)

Polymerization of Styrene

 

\( \text{Li}^+ \)

\( \text{Na}^+ \)

\( \text{Cs}^+ \)

\( k_p^{\pm} \)

160

80

22

\( K \times 10^7 \)

2.2

1.5

0.02

\( k_p^- \times 10^{-4} \)

6.5

6.5

6.5

Data of Bhattacharya et al., J. Phys Chem. 69, p.612 (1965)

So we see that different solvents bring about different degrees of dissociation of the initiator resulting in different specific reaction rates.

Anionic Polymerization

1. Determining the living polymer concentration as a function of time

\(\text{AB} \rightleftharpoons \text{A}^- + \text{B}^+\)

For complete dissociation of the iniator

\(\text{A}^- + M \xrightarrow{k_o} R_1\)

\(R_1 + M \xrightarrow{k_p} R_2\)

\(R_j + M \xrightarrow{k_p} R_{j+1}\)

Assumptions

Initiation is instantaneous, R10 = Io

2. No termination

\(\text{I} + \text{M} \xrightarrow{k_o} R_1\)

\(R_1 + \text{M} \xrightarrow{k_p} R_2\)

\(R_{j-1} + \text{M} \xrightarrow{k_p} R_j\)

Case 1     ko >> kp Immediate rate formulation of primary radical

\( I = I_0 e^{-\frac{k_o}{k_p} \theta} \)


\(\frac{dR_1}{dt} = k_o M I - k_p M R_1\)

\( R_1 = \frac{I_0 k_o}{k_o - k_p} \left[ e^{-\theta} - e^{-\frac{k_o}{k_p} \theta} \right] \)

\(\frac{k_o}{k_p} \gg 1\)

\( I = I_0 e^{-\frac{k_o}{k_p} \theta} \)


\( R_1 = I_0 e^{-\theta} \)

\(\text{at } \theta = 0; \quad R_1 = R_{01} = I_0 \)

Propagation with No termination

\(\frac{dR_1}{dt} = -k_p [R_1][M]\)

\(\frac{dR_2}{dt} = k_p [R_1 - R_2][M]\)

\(\frac{dR_j}{dt} = k_p [R_{j-1} - R_j][M]\)

For the live polymer with the largest chain length n

\(\frac{dR_n}{dt} = k_p R_{n-1} M\)

Summing all these equations

\(\sum_{j=1}^{n} \frac{dR_j}{dt} = \frac{dR^-}{dt} = \sum R_j = 0\)

Constant live polymer concentration

\( R^- = R_{10} = I_0 \)

\(\text{Let } dq = k_p M \, dt\)

\(\frac{dR_1}{d\theta} = -R_1\)

\( t = 0, q = 0, R_1 = I_0 \quad R_1 = R_{10} e^{-\theta} \)

\(\frac{dR_2}{d\theta} = R_1 - R_2\)

\(\frac{dR_2}{d\theta} + R_2 = I_0 e^{-\theta}\)

\( R_2 = I_0 \theta e^{-\theta} \)

\( R_3 = I_0 \frac{\theta^2}{2 \times 1} e^{-\theta} \)

\( R_4 = I_0 \frac{\theta^3}{3 \times 2 \times 1} e^{-\theta} \)

\( R_j = I_0 \frac{\theta^{j-1}}{(j-1)} e^{-\theta} \)

\( y_j = \frac{\theta^{j-1}}{(j-1)} e^{-\theta} \)

Graph of Rj over I0 versus theta, showing two curves labeled R3 and R7 with peaks at different theta values.

Graph of Rj over I0 versus j, displaying two curves with peaks at theta1 and theta2, where theta2 is greater than theta1.

Convert back to real time from scaled time

\(\theta = \frac{M_0}{I_0} \left( 1 - e^{-I_0 k_p t} \right)\)


Very small \( t \) (i.e., small \( I_0 k_p t \))

\(\theta = M_0 k_p t\)

Very large \( t \) (i.e., large \( I_0 k_p t \))

\(\theta = \frac{M_0}{I_0}\)

Graph of theta versus time (t), showing a curve that asymptotically approaches the dashed line representing Mo divided by Io.

Distribution of molecular weights of living polymers

\(\text{NaCl} = \mu_N = (1 + \theta)\)

Graph of mu_N versus theta, showing a linear increasing trend.

\(\mu_w = \frac{1 + 3\theta + \theta^2}{1 + \theta} = 1 + \theta + \frac{\theta}{1 + \theta}\)

Graph of mu_w versus theta, showing two different slopes: slope = 3 for theta much less than 1, and slope = 1 for theta much greater than 1. The graph starts at mu_w = 1 and increases towards mu_w = 2.

\(\text{D} = \frac{\mu_w}{\mu_n} = \frac{1 + 3\theta + \theta^2}{(1 + \theta)^2} = 1 + \frac{\theta}{(1 + \theta)^2}\)

Graph of D versus theta with a peak at theta = 1.0, marked with a black dot and a dashed vertical line indicating symmetry.

Next consider a different set of initiation conditions

Case 2     ko = kp

\(\frac{dI}{dt} = -k_p I M\)

\(\frac{dI}{d\theta} = -I\)

\(I = I_o e^{-\theta}\)

\(R_1 = I_o \theta e^{-\theta}\)

\(R_2 = I_o \frac{\theta^2}{2!} e^{-\theta}\)

\(R_3 = I_o \frac{\theta^3}{3!} e^{-\theta}\)

\(R_n = \frac{I_o \theta^n}{n!} e^{-\theta}\)


Anionic Polymerization in a CSTR

\( I + M \xrightarrow{k_o} R_1 \)

\( R_1 + M \xrightarrow{k_p} R_2 \)

\( R_{j-1} + M \xrightarrow{k_p} R_j \)

Diagram of a cylindrical object with applied moment (M₀) and force (I₀) from the top, along with reaction moment (M) and reaction force (Rj) at the bottom indicating rotational motion.

Monomer Balance

\(\tau \frac{dM}{dt} = M_0 - M - k_o (I) (M) \tau - k_p M \sum_{j}^{R^*} R_j \tau\)

Balance on \( R_1 \)

\(\tau \frac{dR_1}{dt} = R_{1f} - R_1 + \left( k_o (I) M - k_p R_1 M \right)\)

Balance on \( R_j \)

\(\tau \frac{dR_j}{dt} = 0 - R_j + k_p M \left[ R_{j-1} - R_j \right] \tau\)

 

Psuedosteady State Hypothesis (PSSH)

Case 1     ko is essentially (i.e., ko >> kp) infinite. Io is reacted immediately upon mixing with monomer to form R10

Diagram of a cylindrical object with applied moment (M₀) and force (I₀), indicating rotational motion.

\(M_f, \quad R_{10} = R_{1f}\)

\(M_0 \gg I_0, \quad \therefore M_f = M_0\)

\(R_{10} = I_0 = \sum R_j = R^*\)

There is no initiator, \(I\), in the reactor

\(M = \frac{M_0}{1 + \tau k R^*} = \frac{M_0}{1 + \tau k_p R_{10}} = \frac{M_0}{1 + \tau k_p I_0}\)

\(R_j = \frac{R_{j-1} \tau k_p M}{1 + \tau k_p M}\)


\(R_j = \frac{R_{10}}{(1 + \tau k_p M)} \left( \frac{\tau k_p M}{1 + \tau k_p M} \right)^{j-1}\)

\(= R_{10} (1 - \phi) \phi^{j-1} = I_0 (1 - \phi) \phi^{j-1}\)

where \(\phi = \frac{\tau k_p M}{1 + \tau k_p M}\)

\(\mu_n = \frac{\sum j R_j}{\sum R_j} = \frac{\sum j R_j}{I_0}\)

\(\mu_n = \frac{1}{1 - \phi}\)


Substituting for \(M = \frac{M_0}{1 + \tau k_p I_0}\)

\(1 + \tau k_p M = 1 + \frac{\tau k_p M_0}{1 + \tau k_p I_0} = \frac{1 + \tau k_p (M_0 + I_0)}{1 + \tau k_p I_0}\)

\(\frac{\tau k_p M}{1 + \tau k_p M} = \frac{\tau k_p}{1/M + \tau k_p} = \frac{\tau k_p}{\frac{(1 + \tau k_p I_0)}{M_0} + \tau k_p}\)

\(R_j = R_{10} \frac{(1 + \tau k_p I_0)}{1 + \tau k_p (M_0 + I_0)} \left[ \frac{\tau k_p M_0}{1 + \tau k_p (I_0 + M_0)} \right]^{j-1}\)

 

Case 2     ko is finite

\(\tau \frac{dI}{dt} = I_0 - I - k_0 \tau M I\)

\(I = \frac{I_0}{1 + \tau k_0 M}\)

\(M = \frac{M_0}{1 + \tau k_0 (I) + \tau k_p I_0}\)

\(R_1 = \frac{\tau k_0 M I}{1 + \tau k_p M} \quad (R_{1f} = 0)\)

\(R_2 = \frac{R_1 k_p M \tau}{1 + \tau k_p M}\)

\(R_j = R_{j-1} \left( \frac{k_p M \tau}{1 + \tau k_p M} \right)\)

\(R_j = \frac{\tau k_0 M I}{1 + \tau k_p M} \left( \frac{\tau k_p M}{1 + \tau k_p M} \right)^{j-1}\)

\(R_j = \frac{\tau k_0 M I_0}{(1 + \tau k_p M)^{j} + \tau k_0 M} \left( \frac{\tau k_p M}{1 + \tau k_p M} \right)^{j-1}\)

\(j = 1\)

\(R_1 = \frac{\tau M I_0}{(1 + \tau k_p M) \left( \frac{1}{k_0} + \tau M \right)}\)

\(k_0 = \infty\)

\(R_1 = \frac{I_0}{1 + \tau k_p M}\)

 

* All chapter references are for the 1st Edition of the text Essentials of Chemical Reaction Engineering .

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