Chapter 9: Reaction Mechanisms, Pathways, Bioreactions and Bioreactors

Derive: Case 2 Rate Law

\( M = M_o (1 - p) \)

\(- \frac{dM}{dt} = k' M^{5/2} \)

\( = k M_o^{5/2} (1 - p)^{5/2} = +M_o \frac{dp}{dt} \)

\(\frac{dp}{dt} = k M_o^{3/2} (1 - p)^{5/2} \)

Integrating with \( t = 0 \), \( p = 0 \)

\(\frac{1}{(1 - p)^{3/2}} = \frac{3}{2} k M_o^{3/2} t + 1 \)

Back to Chapter 9