Chapter 9: Reaction Mechanisms, Pathways, Bioreactions and Bioreactors


Derive: Number Average Molecular Weight:

Basis: 100 grams total

\( N_A = \frac{M_A}{MW_A} = \frac{95}{10,000} = 0.95 \times 10^{-2} \text{ moles of A} \)

\( N_B = \frac{M_B}{MW_B} = \frac{5}{100} = 5 \times 10^{-2} \text{ moles of B} \)

\( N_t = N_A + N_B = 5.95 \times 10^{-2} \text{ moles total} \)

\( y_A = \frac{N_A}{N_t} \)

\( y_B = \frac{N_B}{N_t} \)

\( y_A = 0.16 \quad . \quad y_B = 0.84 \)

\( \bar{M}_n = (0.16)(10000) + (0.84)(100) = 1684 \)

Back to Example

Back to Chapter 9