Chapter 3 Example

Writing -r_A Solely as a Function of X. 

Write the rate law for the elementary liquid phase reaction

solely in terms of conversion. The feed to the batch reactor is equal molar A and B with C_A0 = 2 mol/dm³ and k_A= .01 (dm³/mol)⁴1/s.

Hint 1: What is the rate law?

Hint 2: What is the concentration of A?

Hint 3: What is the concentration of B?

Full Solution

        What is the rate law?

        The reaction is elementary so what happens to the coefficients from the reaction?

Back to Problem

        What is the concentration of A?

        Liquid phase, v = v_o (no volume change)

Back to Problem





























Hint 3

What is the concentration of B?

What is Θ_B?

Equal molar

Species A is the limiting reactant because the feed is equal molar in A and B, and two moles of B consumes 3 moles of A.

Back to Problem

Write the rate law for the elementary liquid phase reaction

solely in terms of conversion. The feed to the batch reactor is equal molar A and B with C_A0 = 2 mol/dm³ and k_A= .01 (dm³/mol)⁴1/s.

1) Rate Law: -r_A=kC³_AC²_B

2) Stoichiometry:

Species A

Liquid phase, v = v_o (no volume change)

Species B

What is Θ_B?

Species A is the limiting reactant because the feed is equal molar in A and B, and two moles of B consumes 3 moles of A.

We now have -r_A=f(X) and can size reactors or determine batch reaction times.

Back to Chapter 3