Example 8-3 Adiabatic Isomerization of Normal Butane  |POLVER05_0
d(X)/d(V) =  -ra/Fa0  #
Ca0 =  9.3 #
Fa0 =  .9*163 #
T =  330+43.3*X #
Kc =  3.03*exp(-830.3*((T-333)/(T*333))) #
k =  31.1*exp(7906*(T-360)/(T*360)) #
Xe =  Kc/(1+Kc) #
ra =  -k*Ca0*(1-(1+1/Kc)*X) #
rate =  -ra #
V(0)=0
X(0)=0
V(f)=3.3