Example 10-3 Fixed-Bed Reactor Design |POLVER05_0 d(X)/d(w) = -rt/FTo # FTo = 50 # k = .00087 # KT = 1.038 # KB = 1.39 # alpha = 0.000098 # Po = 40 # PTo = 0.3*Po # y = (1-alpha*w)^0.5 # P = y*Po # PH2 = PTo*(1.5-X)*y # PB = PTo*X*y # PT = PTo*(1-X)*y # rt = -k*PT*PH2/(1+KB*PB+KT*PT) # RATE = -rt # w(0)=0 X(0)=0 w(f)=10000